SOLUTION: andrew can paint the neighbors house 5 times as fast asn Bailey. the year andrew and bailey worked together, it took them 1 day. how long would it take each to paint the house?
Algebra ->
Rate-of-work-word-problems
-> SOLUTION: andrew can paint the neighbors house 5 times as fast asn Bailey. the year andrew and bailey worked together, it took them 1 day. how long would it take each to paint the house?
Log On
Question 595163: andrew can paint the neighbors house 5 times as fast asn Bailey. the year andrew and bailey worked together, it took them 1 day. how long would it take each to paint the house? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Andrew can paint the neighbors house 5 times as fast as Bailey. the year Andrew and Bailey worked together, it took them 1 day.
How long would it take each to paint the house?
:
Let t = time for Andrew to paint the house
then
5t = time required by Bailey to do it
:
Write a shared work equation; the completed job = 1 + = 1
multiply by 5t to clear the denominators, results:
5 + 1 = 5t
6 = 5t
t = 6/5
t = 1.2 days for Andrew
then
5(1.2) = 6 days for Bailey
