Find the roots for the equation. Leave in simplest radical form.
x^2-3x=9 Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Find the roots for the equation. Leave in simplest radical form.
x^2-3x=9
x^2-3x-9=0
solve by quadratic formula
a=1, b=-3, c=-9
x=[-(-3)±√(-3)^2-4*1*-9)]/2*1
x=[3±√(9+36)]/2
x=(3±√45)/2
x=(3±3√5)/2
x=3/2(1±√5
..
x=(3/2)(1+√5)
or
x=(3/2)(1-√5)
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