SOLUTION: Given that {{{log(2,(x))}}} = m and {{{log(2,(y))}}} = n, express in terms of m and n: A) {{{log(2,(8x^2y))}}} B) {{{log(2,(y/(2x)))}}}

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Given that {{{log(2,(x))}}} = m and {{{log(2,(y))}}} = n, express in terms of m and n: A) {{{log(2,(8x^2y))}}} B) {{{log(2,(y/(2x)))}}}      Log On


   

Question 594784: Given that log%282%2C%28x%29%29 = m and log%282%2C%28y%29%29 = n, express in terms of m and n:
A) log%282%2C%288x%5E2y%29%29
B) log%282%2C%28y%2F%282x%29%29%29
Answer by AnlytcPhil(1807) About Me  (Show Source):
You can put this solution on YOUR website!
Given that log%282%2C%28x%29%29 = m and log%282%2C%28y%29%29 = n, express in terms of m and n:
Rules needed to do problems:

log%28B%2C%28B%29%29=1, log%28B%2C%28B%5EA%29%29=A, log%28B%2CACD%29=log%28B%2C%28A%29%29%2Blog%28B%2C%28C%29%29%2Blog%28B%2C%28D%29%29, log%28B%2C%28A%2FC%29%29=log%28B%2C%28A%29%29-log%28B%2C%28C%29%29, log%28B%2C%28A%5EC%29%29=C%2Alog%28B%2C%28A%29%29

A) log%282%2C%288x%5E2y%29%29 = log%282%2C%288%29%29 + log%282%2C%28x%5E2%29%29 + log%282%2C%28y%29%29 = log%282%2C%282%5E3%29%29 + 2log%282%2C%28x%29%29 + log%282%2C%28y%29%29 = 3 + 2log%282%2C%28x%29%29 + log%282%2C%28y%29%29 = 3 + 2m + n 

B) log%282%2C%28y%2F%282x%29%29%29 = log%282%2C%28y%29%29 - log%282%2C%282x%29%29 = log%282%2C%28y%29%29 - (log%282%2C%282%29%29 + log%282%2C%28x%29%29) = log%282%2C%28y%29%29 - log%282%2C%282%29%29 - log%282%2C%28x%29%29 = n - 1 - m

Edwin