SOLUTION: If a stone is tossed from the top of a 330 meter building the height of the stone as a function of time is given by h(t)=-9.8t^2-10t+330 where is it in seconds and height is in met
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-> SOLUTION: If a stone is tossed from the top of a 330 meter building the height of the stone as a function of time is given by h(t)=-9.8t^2-10t+330 where is it in seconds and height is in met
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Question 594383: If a stone is tossed from the top of a 330 meter building the height of the stone as a function of time is given by h(t)=-9.8t^2-10t+330 where is it in seconds and height is in meters. After how many seconds will the stone hit the ground? Round to the nearest hundredths place; include units in your answer. Found 2 solutions by solver91311, Alan3354:Answer by solver91311(24713) (Show Source):
The ground is height = 0, so set the function equal to zero and solve the resulting quadratic equation for . Discard the negative root since you don't care what happened before you threw the stone (do you?).
Super Double Plus Extra Credit:
Which way was the stone thrown; up or down? Hint: look at the coefficient on the first degree term. Up is +, Down is -.
John
My calculator said it, I believe it, that settles it
You can put this solution on YOUR website! If a stone is tossed from the top of a 330 meter building the height of the stone as a function of time is given by h(t)=-9.8t^2-10t+330
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That might be true somewhere, but on Earth, it's
h(t)=-4.9t^2-10t+330
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-4.9 m/sec/sec, negative falling, approximate value.
