SOLUTION: Write as a single log of a single base. 3log[e]24 - ln36 - ln16

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Write as a single log of a single base. 3log[e]24 - ln36 - ln16      Log On


   

Question 594305: Write as a single log of a single base.
3log[e]24 - ln36 - ln16
Answer by mamiya(56) About Me  (Show Source):
You can put this solution on YOUR website!
3log[e]24 - ln36 - ln16 = 3ln24 - ln36 - ln16
= ln (24^3) - ( ln36 + ln16 )
= ln 13824 - ln ( 36*16)
= ln 13824 - ln 576
= ln ( 13824/576)
= ln 24

so 3log[e]24 - ln36 - ln16 = ln(24)