SOLUTION: f(x)= -2x^2+4x+1 Find the vertex and axis of symmetry of the graph of the function.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: f(x)= -2x^2+4x+1 Find the vertex and axis of symmetry of the graph of the function.      Log On


   

Question 59403: f(x)= -2x^2+4x+1
Find the vertex and axis of symmetry of the graph of the function.
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=-2x%5E2%2B4x%2B1
Find the vertex and axis of symmetry of the graph of the function.
When a quadratic equation is in standard form f%28x%29=ax%5E2%2Bbx%2Bc, you can find the axis of symmetry and the x coordinate of the vertex with the formula highlight%28x=-b%2F2a%29
a=-2, b=4, c=1
The axis of symmetry and x coordinate of the vertex is:
x=-%284%29%2F%282%28-2%29%29
x=%28%28-4%29%29%2F%28-4%29
highlight%28x=1%29 is the axis of symmetry
Find f(1) to find the y coordinate of the vertex:
f%281%29=-2%281%29%5E2%2B4%281%29%2B1
f%281%29=-2%281%29%2B4%2B1
f%281%29=-2%2B4%2B1
f%281%29=3
The vertex is: (1,3)
Happy Calculating!!!