|  | 
| 
 
 
| Question 593978:  A small farm has 70 acres of space to plant. The farmer wants to grow corn and green beans. It costs $60 per acre to grow the corn and $30 per acre to grow the green beans. The farmer has $1800 to use for planting the vegetables. It takes the farmer 3 days to plant each acre of corn and 4 days to plant each acre of green beans. There are 120 days available to plant the vegetables. When the farmer sells the vegetables, he can expect to make a profit of $180 per acre for the corn and $100 per acre for the green beans. How many acres should the farmer allow for each vegetable in order to maximize profit?
 What are the equations I should use to solve this problem?
 Answer by ankor@dixie-net.com(22740)
      (Show Source): 
You can put this solution on YOUR website! A small farm has 70 acres of space to plant. The farmer wants to grow corn and green beans.
 It costs $60 per acre to grow the corn and $30 per acre to grow the green beans.
 The farmer has $1800 to use for planting the vegetables.
 It takes the farmer 3 days to plant each acre of corn and 4 days to plant each acre of green beans.
 There are 120 days available to plant the vegetables.
 When the farmer sells the vegetables, he can expect to make a profit of $180 per acre for the corn and $100 per acre for the green beans.
 How many acres should the farmer allow for each vegetable in order to maximize profit?
 :
 Let x = no. of acres for corn
 Let y = no. of acres for beans
 :
 Write an equation for each constraint, put each equation the slope intercept for for graphing
 :
 The Acerage equation
 x + y =< 70
 y = -x + 70, (Red)
 :
 Cost equation
 60x + 30y =< 1800
 30y = -60x + 1800
 y = -2x + 60, Green
 :
 Time equation
 3x + 4y =< 120
 4y = -3x + 120
 y = -.75x + 30 (blue)
 :
 Obviously, all values are positive
 x => 0
 y => 0
 ;
 Graph all 3 equations on the same grid
 
  :
 From the graph we can see an intersection at x = 24, y = 12
 Check and you can see these values will give us a cost of $1800 and time of 120 days
 We can ignore the acreage equation, only 36 acres can be planted
 :
 "When the farmer sells the vegetables, he can expect to make a profit of $180 per acre for the corn and $100 per acre for the green beans."
 Profit:
 24(180) + 12(100) =
 4320 + 1200 = $5520 max profit
 :
 But another corner is x=30, y=0; 30 acres of corn and no beans
 It also will cost $1800 and but only 90 days to plant
 Profit: 30(180) = $5400, slightly less, but less time required
 :
 You can check the 3rd corner. x = 0; y = 30, 30 acres of beans and no corn
 | 
  
 | 
 |  |  |