SOLUTION: jASON HAD TO SUBMIT 5 PROJECTS. HE SCORED 88,79,76 AND 90 POINTS OUT OF 100 ON 4 PROJECTS. WHAT WOULD THE SCORE BE ON THE FIFTH PROJECT SO THAT THE AVERAGE IS 83?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: jASON HAD TO SUBMIT 5 PROJECTS. HE SCORED 88,79,76 AND 90 POINTS OUT OF 100 ON 4 PROJECTS. WHAT WOULD THE SCORE BE ON THE FIFTH PROJECT SO THAT THE AVERAGE IS 83?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 593912: jASON HAD TO SUBMIT 5 PROJECTS. HE SCORED 88,79,76 AND 90 POINTS OUT OF 100 ON
4 PROJECTS. WHAT WOULD THE SCORE BE ON THE FIFTH PROJECT SO THAT THE AVERAGE IS 83?

Answer by tutorcecilia(2152) About Me  (Show Source):
You can put this solution on YOUR website!
jASON HAD TO SUBMIT 5 PROJECTS. HE SCORED 88,79,76 AND 90 POINTS OUT OF 100 ON
4 PROJECTS. WHAT WOULD THE SCORE BE ON THE FIFTH PROJECT SO THAT THE AVERAGE IS 83?
%2888%2B79%2B76%2B90%2Bx%29%2F%285%29=83
%28333%2Bx%29%2F%285%29=83
333+x = (83)(5)
333+x) = 415
x=415-333
x=82
.
check by plugging 82 back into the equation (let x=82).