Question 59388This question is from textbook
: Science and medicine. Martina leaves home at 9 A.M., bicycling at a rate of
24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time
will John catch up with Martina?
This question is from textbook
Answer by funmath(2933)   (Show Source):
You can put this solution on YOUR website! Science and medicine. Martina leaves home at 9 A.M., bicycling at a rate of
24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina?
:
The distance formula is: , d=distance, r=rate, and t=time.
:
Martina's r=24 mi/h
Let Martina's time be: t (we don't know what it is)
Then Martina's distance d=24t
:
John's r=48 mi/h
John left two hours later so he traveled 2 hours less than Martina: t-2
Then John's distance d=48(t-2)
:
John Catches up to Martina, so their distances are equal.
Problem to solve:
24t=48(t-2)
24t=48t-96
-48t+24t=-48t+48t-96
-24t=-96
-24t/-24=-96/-24
t=4
That means that Martina traveled for 4 hours.
She left at 9am, four hours later makes it 1pm.
Happy Calculating!!!
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