SOLUTION: Geometry. The length of a rectangular playing field is 5 ft less than twice its width.
If the perimeter of the playing field is 230 ft, find the length and width of the field.
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-> SOLUTION: Geometry. The length of a rectangular playing field is 5 ft less than twice its width.
If the perimeter of the playing field is 230 ft, find the length and width of the field.
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Question 59385This question is from textbook
: Geometry. The length of a rectangular playing field is 5 ft less than twice its width.
If the perimeter of the playing field is 230 ft, find the length and width of the field. This question is from textbook
You can put this solution on YOUR website! Geometry. The length of a rectangular playing field is 5 ft less than twice its width.
If the perimeter of the playing field is 230 ft, find the length and width of the field.
:
The formula for the perimeter of a rectangle is , p=perimeter, W=width, L=lenght
:
Let width (W)=W
Then lenght (L)=2W-5
P=230 ft
:
Problem to solve:
230=2W+2(2W-5)
230=2W+4W-10
230=6W-10
230+10=6W-10+10
240=6W
240/6=6W/6
40=W
:
W=40 ft
L=2w-5=2(40)-5=80-5=75 ft
:
Check:
230=2(40)+2(75) ?
230=80+150 ?
230=230 !!! Looks good.
Happy Calculating!!!