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Question 593804: Find four consecutive even integers such that if the sum of the first and third is multiplied by 4 the result is 10 more than 7 times the fourth.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Find four consecutive even integers
x, (x+2), (x+4), (x+6)
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such that if the sum of the first and third is multiplied by 4 the result is 10 more than 7 times the fourth.
4[x + (x+4)] = 7(x+6) + 10
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4(2x+4) = 7x + 42 + 10
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8x + 16 = 7x + 52
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8x - 7x = 52 - 16
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x = 36 is he 1st integer
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36, 38, 40, 42 the four consecutive integers
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Check this in the statement:
"sum of the first and third is multiplied by 4 the result is 10 more than 7 times the fourth"
4(36 + 40) = 7(42) + 10
304 = 294 + 10
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