SOLUTION: Suppose an opaque jar contains 5 red marbles and 10 green marbles. I experiment picking 2 marbles from the jar without replacing the first one.
1. What is the probability of get
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-> SOLUTION: Suppose an opaque jar contains 5 red marbles and 10 green marbles. I experiment picking 2 marbles from the jar without replacing the first one.
1. What is the probability of get
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Question 593109: Suppose an opaque jar contains 5 red marbles and 10 green marbles. I experiment picking 2 marbles from the jar without replacing the first one.
1. What is the probability of getting a green marble first and a red marble second?
2. What is the probability of getting a green marble and a red marble? How is this different from question #1?
For the 1st question I did this: (5x10)/(15x14)= 50/210 = 5/21 (am pretty sure that is right)
For the 2nd question I am stumped...I thought it would be the same answer but something keeps nagging at me that I am missing something. I thought about this: (5)squared +(10)squared/(15x14) = 125/210.595 or 59.5% I really don't understand how the questions are that different..or at least I know they are asking 2 different probable outcomes but don't know how to explain the difference. Can you please help me? Thanks!
Glennys
You can put this solution on YOUR website! Suppose an opaque jar contains 5 red marbles and 10 green marbles. I experiment picking 2 marbles from the jar without replacing the first one.
1. What is the probability of getting a green marble first and a red marble second?
Ans: (10/15)(5/14) = 50/210 = 5/21
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2. What is the probability of getting a green marble and a red marble? How is this different from question #1?
# of ways to succeed: 5*10 = 50
# of random pairs: 15C2 = 105
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P(red AND green) = 50/105 = 10/21
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