SOLUTION: An object that is projected straight downward with initial velocity v feet per second travels a distance s+vt +16(square), where t=time in seconds. If Ramon is standing on a balcon
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Question 593050: An object that is projected straight downward with initial velocity v feet per second travels a distance s+vt +16(square), where t=time in seconds. If Ramon is standing on a balcony 84 feet above the ground and throws a penny staright down with an initial velocity of 10 feet per second, in how many seconds will it reach the ground? Answer by solver91311(24713) (Show Source):
Your initial velocity data is expressed incorrectly and your function has a sign error.
The initial position is at 84 feet up (positive) and the sign of initial velocity is dependent on whether he threw it upward or downward. He threw it down so the initial velocity is not 10 feet per second, it is -10 feet per second. Given the difficulty of moving the center of the earth, the acceleration downward must ALWAYS be negative.
Solve the factorable quadratic for . Discard the negative root (you don't care what happened BEFORE Ramon threw the penny).
John
My calculator said it, I believe it, that settles it
