Question 593015: Find an equation for the parabola with focus (4,-6) and vertex at (3, -6)
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Find an equation for the parabola with focus (4,-6) and vertex at (3, -6)
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Standard form of equation for a parabola that opens rightwards: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of vertex.
For given parabola:
vertex: (3,-6)
axis of symmetry: y=-6
p=1 (distance from focus to vertex on axis of symmetry)
4p=4
Equation of parabola:
(y+6)^2=4(x-3)
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