SOLUTION: I am curious as how to accurately solve for X in the problem: √3-X(Numerator) √2x(Denominator) equals 2 I have squared both sides leading me to (3-x)/(2x)=4 Howe

Algebra ->  Rational-functions -> SOLUTION: I am curious as how to accurately solve for X in the problem: √3-X(Numerator) √2x(Denominator) equals 2 I have squared both sides leading me to (3-x)/(2x)=4 Howe      Log On


   

Question 592856: I am curious as how to accurately solve for X in the problem:
√3-X(Numerator)
√2x(Denominator)
equals 2
I have squared both sides leading me to (3-x)/(2x)=4 However, I do not know what to do after that step. I have tried elimination but do not get the right answer. I would greatly appreciate help on this subject. Thank you.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for X in the problem:
√3-X(Numerator)
√2x(Denominator)
:
%28sqrt%283-x%29%29%2F%28sqrt%282x%29%29 = 2
:
%28%283-x%29%29%2F%28%282x%29%29 = 4
multiply both sides by 2x
3 - x = 4(2x)
3 - x = 8x
3 = 8x + x
3 = 9x
x = 3/9 = 1/3