SOLUTION: The equation is h(t)=-16t2+1000. An object is being dropped from a height of 1000 feet. How long would it take to drop to 500 feet?

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Question 592319: The equation is h(t)=-16t2+1000. An object is being dropped from a height of 1000 feet. How long would it take to drop to 500 feet?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
The equation is h(t)=-16t2+1000.
An object is being dropped from a height of 1000 feet.
How long would it take to drop to 500 feet?
:
When it has dropped 500', it will be 500' above the ground , therefore h(t) = 500
-16t^2 + 1000 = 500
-16t^2 = 500 - 1000
-16t^2 = -500
Multiply both sides by -1
16t^2 = 500
divide both sides by 16
t^2 = 500%2F16
t^2 = 31.25
t = sqrt%2831.25%29
t = 5.59 seconds to drop 500 ft