SOLUTION: Let ABCD be a trapezoid with parallel bases AD and BC. The diagonals meet at O. Prove that AO/CO=OD/BO

Algebra ->  Geometry-proofs -> SOLUTION: Let ABCD be a trapezoid with parallel bases AD and BC. The diagonals meet at O. Prove that AO/CO=OD/BO      Log On


   

Question 592225: Let ABCD be a trapezoid with parallel bases AD and BC. The diagonals meet at O.
Prove that AO/CO=OD/BO
Found 2 solutions by 253689, ikleyn:
Answer by 253689(1) About Me  (Show Source):
Answer by ikleyn(52887) About Me  (Show Source):
You can put this solution on YOUR website!
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It is so because the triangles AOB and COD are similar.

(The vertices of the triangles are listen in the corresponding order).