SOLUTION: What is the solution(s) to log base 4 of 4x + log base 4 of (x+3) = 2

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Question 592064: What is the solution(s) to log base 4 of 4x + log base 4 of (x+3) = 2
Answer by lwsshak3(11628) About Me  (Show Source):
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What is the solution(s) to log base 4 of 4x + log base 4 of (x+3) = 2
log4[(4x)(x+3)]=2
convert to exponential form: base(4) raised to log of number(2)=number(4x)(x+3)
4^2=(4x)(x+3)=16
4x^2+12x=16
4x^2+12x-16=0
x^2+3x-4=0
(x+4)(x-1)-0
x=-4 (reject,x>0)
or x=1