SOLUTION: 50. ab+b^2/4ab^5 over a+b/6a^2b^4 yah another division problem i do not understand. can you lend some of your wounderful knowledge. thanks

Algebra ->  Expressions-with-variables -> SOLUTION: 50. ab+b^2/4ab^5 over a+b/6a^2b^4 yah another division problem i do not understand. can you lend some of your wounderful knowledge. thanks      Log On


   

Question 59184: 50. ab+b^2/4ab^5 over a+b/6a^2b^4 yah another division problem i do not understand. can you lend some of your wounderful knowledge. thanks
Answer by Cintchr(481) About Me  (Show Source):
You can put this solution on YOUR website!
There is a rule that says ...
+%28a%2Fb%29%2F%28c%2Fd%29+=+ad%2Fbc+
Herre is your original equation.
+%28%28ab%2Bb%5E2%29%2F%284ab%5E5%29%29%2F%28%28a%2Bb%29%2F%286a%5E2b%5E4%29%29+
Rewrite it
+%28%28ab%2Bb%5E2%29%286a%5E2b%5E4%29%29%2F%28%284ab%5E5%29%28a%2Bb%29%29+
Factor the binomial in the numerator
+%28b%28a%2Bb%29%286a%5E2b%5E4%29%29%2F%28%284ab%5E5%29%28a%2Bb%29%29+
Cancel the a+b in the numerator and the denominator
+%28b%286a%5E2b%5E4%29%29%2F%284ab%5E5%29+
combine the "b" values in the numerator
+%286a%5E2b%5E5%29%2F%284ab%5E5%29+
So you can see how the rest of the fraction reduces ... we will break it apart into three separate values
+6%2F4+ +a%5E2%2Fa+ +b%5E5%2Fb%5E5+
reduce each one ...
+3%2F2+ +a%2F1+ +1%2F1+
bring the values back together into one fraction
+3a%2F2+