SOLUTION: Liquids A and B are mixed in the ratio 2:7 (by volume). What volume of liquid would be present in the solution if it contained 56 ml of liquid B?
Algebra ->
Percentage-and-ratio-word-problems
-> SOLUTION: Liquids A and B are mixed in the ratio 2:7 (by volume). What volume of liquid would be present in the solution if it contained 56 ml of liquid B?
Log On
Question 591610: Liquids A and B are mixed in the ratio 2:7 (by volume). What volume of liquid would be present in the solution if it contained 56 ml of liquid B? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Liquids A and B are mixed in the ratio 2:7 (by volume).
What volume of liquid would be present in the solution if it contained 56 ml of liquid B?
:
A ratio equation to find the amt of liquid A
: =
Cross multiply
7A = 56 * 2
7A = 112
A = 112/7
A = 16 ml
:
Total volume: 56 + 16 = 72 ml
