SOLUTION: {{{ 4x^2 +x-6=0 }}}

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Question 591533: +4x%5E2+%2Bx-6=0+
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

4x%5E2%2Bx-6=0 Start with the given equation.


Notice that the quadratic 4x%5E2%2Bx-6 is in the form of Ax%5E2%2BBx%2BC where A=4, B=1, and C=-6


Let's use the quadratic formula to solve for "x":


x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


x+=+%28-%281%29+%2B-+sqrt%28+%281%29%5E2-4%284%29%28-6%29+%29%29%2F%282%284%29%29 Plug in A=4, B=1, and C=-6


x+=+%28-1+%2B-+sqrt%28+1-4%284%29%28-6%29+%29%29%2F%282%284%29%29 Square 1 to get 1.


x+=+%28-1+%2B-+sqrt%28+1--96+%29%29%2F%282%284%29%29 Multiply 4%284%29%28-6%29 to get -96


x+=+%28-1+%2B-+sqrt%28+1%2B96+%29%29%2F%282%284%29%29 Rewrite sqrt%281--96%29 as sqrt%281%2B96%29


x+=+%28-1+%2B-+sqrt%28+97+%29%29%2F%282%284%29%29 Add 1 to 96 to get 97


x+=+%28-1+%2B-+sqrt%28+97+%29%29%2F%288%29 Multiply 2 and 4 to get 8.


x+=+%28-1%2Bsqrt%2897%29%29%2F%288%29 or x+=+%28-1-sqrt%2897%29%29%2F%288%29 Break up the expression.


So the solutions are x+=+%28-1%2Bsqrt%2897%29%29%2F%288%29 or x+=+%28-1-sqrt%2897%29%29%2F%288%29