Question 591513: log base 4 of 3x = log base 32 of 7x
whats x???
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! log base 4 of 3x = log base 32 of 7x
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log4(3x) = log32(7x)
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= log(3x)/log(4) = log(7x)/log(32)
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Let the base be 2:
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= log2(3x)/2 = log2(7x)/5
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= log(3x) = (2/5)log(7x)
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= log(3) + log(x) = (2/5)log(7) + (2/5)log(x)
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= (3/5)log(x) = (2/5)log(7)- log(3)
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log(x^(3/5)) = log[7^(2/5)/3]
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x^(3/5) = 7^(2/5) / 3
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x^(3/5) = 0.7260
x = 0.7260^(5/3)
x = 0.5864
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Cheers,
Stan H.
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