SOLUTION: Express the vertex of the quadratic 2x^2 - 3x + 5 as an ordered pair

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Express the vertex of the quadratic 2x^2 - 3x + 5 as an ordered pair      Log On


   

Question 59146This question is from textbook Elementary and Intermediate Algebra
: Express the vertex of the quadratic 2x^2 - 3x + 5 as an ordered pair This question is from textbook Elementary and Intermediate Algebra

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
2x^2 - 3x + 5
------------
Rewrite as:
2x^2-3x=y-5
2(x^2-(3/2)x = y-5
(x^2-(3/2)x+(3/4)^2 = (1/2)y-(5/2)+(9/16)
x^2-(3/2)x+(3/4)^2=(1/2)y-(40/16)+(9/16))
(x-(3/4))^2 = (1/2)(y)-(31/16)
(x-(3/4))^2 = (1/2)(y-31/8)
Vertex at (3/4,31/8)
Cheers,
Stan H.