SOLUTION: In a car race there are 6 chevy's, 4 fords, and 2 pontiacs. How many different ways can the 12 cars finish if we consider the make of the cars only?

Algebra ->  Probability-and-statistics -> SOLUTION: In a car race there are 6 chevy's, 4 fords, and 2 pontiacs. How many different ways can the 12 cars finish if we consider the make of the cars only?       Log On


   

Question 591402: In a car race there are 6 chevy's, 4 fords, and 2 pontiacs. How many different ways can the 12 cars finish if we consider the make of the cars only?
Found 2 solutions by scott8148, stanbon:
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
12! / (6! * 4! * 2!)

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
In a car race there are 6 chevy's, 4 fords, and 2 pontiacs. How many different ways can the 12 cars finish if we consider the make of the cars only?
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Ans: 12!/(6!*4!*2!) = 13860 ways
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Cheers,
Stan H.