SOLUTION: The length of a rectangle is 3 more than twice its width. The perimeter is 48 feet. Find the width. Hint: You did this in Module 3 Assignment 5. Now you have to write the equation

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Question 59120: The length of a rectangle is 3 more than twice its width. The perimeter is 48 feet. Find the width. Hint: You did this in Module 3 Assignment 5. Now you have to write the equation and solve it.
a. 16
b. 7
c. 8
d. 21
e. 24

Answer by funmath(2933) About Me  (Show Source):
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The length of a rectangle is 3 more than twice its width. The perimeter is 48 feet. Find the width. Hint: You did this in Module 3 Assignment 5. Now you have to write the equation and solve it.
a. 16
highlight%28b%29. 7
c. 8
d. 21
e. 24
:
Formula for the perimeter of a rectangle is: highlight%28P=2L%2B2W%29, P is perimeter, L is length, W is width.
Let Width (W) be:x
Then length (L)is: 2x+3
Perimeter (P) is: 48
Problem to solve:
48=2(2x+3)+2(x)
48=4x+6+2x
48=6x+6
48-6=6x+6-6
42=6x
42/6=6x/6
7=x
Width is:x=7 (b)
Happy Calculating!!!