SOLUTION: find two consecutive integers such that the sum of twice the smaller and 3 times the larger is 163
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Question 591121
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find two consecutive integers such that the sum of twice the smaller and 3 times the larger is 163
Answer by
mananth(16946)
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let the two consequtive integers be x & (x+1)
2x+3(x+!)= 163
2x+3x+3=163
5x+3=163
-3
5x=160
/5
x=32
32, and 33