Question 590978: a parking meter contains $27.05 in dimes and quarters. There are 146 coins in the meter. How many of each type are in the meter? Found 2 solutions by Alan3354, edjones:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! a parking meter contains $27.05 in dimes and quarters. There are 146 coins in the meter. How many of each type are in the meter?
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d + q = 146
10d + 25q = 2705
Can you finish it?
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Or,
If it's 146 dimes, it's worth 1460 cents.
Each dime replaced by a quarter adds 15 cents.
2705 - 1460 = 1245
1245/15 = q
You can put this solution on YOUR website! Let q=number of quarters & d=number of dimes.
d+q=146
d=146-q
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.1d+.25q=27.05
.1(146-.1q)+.25q=27.05
14.6-.1q+.25q=27.05
.15q=12.45
q=83 quarters
27.05-.25*83=6.3
6.3*10=63 dimes
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Ed
