SOLUTION: I thought I knew how to do these but I obviously do not because I missed them on my homework assignment. Can someone explain this to me Solve: b^2 + b - 6 = 0

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I thought I knew how to do these but I obviously do not because I missed them on my homework assignment. Can someone explain this to me Solve: b^2 + b - 6 = 0      Log On


   



Question 590962: I thought I knew how to do these but I obviously do not because I missed them on my homework assignment. Can someone explain this to me
Solve:
b^2 + b - 6 = 0

Found 2 solutions by scott8148, Earlsdon:
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
factoring ___ (b + 3)(b - 2) = 0

zero product: if the product is zero, then any (or all) of the factors may be zero

b + 3 = 0 ___ b = -3

b - 2 = 0 ___ b = 2

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for b:
b%5E2%2Bb-6+=+0 Factor the trinomial.
%28b-2%29%28b%2B3%29+=+0 Apply the zero product rule:
b-2+=+0 or b%2B3+=+0 therefore:
b+=+2 or b+=+-3