SOLUTION: Would someone teach me how to do these? and, would they be worked exactly the same? Solve: b^2 + b - 6 = 0 c^2 + c = 0

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Would someone teach me how to do these? and, would they be worked exactly the same? Solve: b^2 + b - 6 = 0 c^2 + c = 0      Log On


   

Question 590956: Would someone teach me how to do these? and, would they be worked exactly the same?
Solve:
b^2 + b - 6 = 0

c^2 + c = 0
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Would someone teach me how to do these? and, would they be worked exactly the same?
Solve:
b^2 + b - 6 = 0
There's more than one way.
This one can be factored.
b^2 + b - 6 = 0
(b + 3)*(b - 2) = 0
----
If the product is 0, either
b+3 = 0 --> b = -3
or
b-2 = 0 --> b = 2
===============================
c^2 + c = 0
This one factors also
c*(c + 1) = 0
Either c = 0
or c = -1