SOLUTION: Two airplanes leave the Atalnta airport at th esame time, traveling in opposite directions. One plane travels 30 miles per hour faster than the other. After 3 hours, the planes ar

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Question 59074: Two airplanes leave the Atalnta airport at th esame time, traveling in opposite directions. One plane travels 30 miles per hour faster than the other. After 3 hours, the planes are 3150 miles apart. what is the rate of each plane?
Answer by funmath(2933) About Me  (Show Source):
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Two airplanes leave the Atalnta airport at the same time, traveling in opposite directions. One plane travels 30 miles per hour faster than the other. After 3 hours, the planes are 3150 miles apart. what is the rate of each plane?
distance (d) = rate (r)* time(t) highlight%28d=rt%29
Time for both planes is: t=3
One planes rate (r) is: x+30
The other's rate (r) is: x
The distance of one plane is: rt=tr=3(x+30)
The distance of the other is: rt=tr=3x
Since they're going in oppostie directions, if we add their two distances together you get: 3150
:
The equation to solve is:
3(x+30)+3x=3150
3x+90+3x=3150
6x+90=3150
6x+90-90=3150-90
6x=3060
6x/6=3060/6
x=510
:
One plane flew at: x+30=510+30=540 mph
The other flew at: x=510 mph
:
Check if both planes flew at that rate for 3 hours would they be 3150 miles apart?
3(540)+3(510)=3150
1620+1530=3150
3150=3150 We're right!!
Happy Calculating!!!