SOLUTION: Assume that log 2 = .301 and log 3 = .477, Solve 1)log 1/9 2)log 30 3)log 5 4)log 0.006

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Question 590586: Assume that log 2 = .301 and log 3 = .477, Solve
1)log 1/9
2)log 30
3)log 5
4)log 0.006
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Assume that log 2 = .301 and log 3 = .477, Solve
1)log 1/9
=log 1/3^2
=log 3^-2
=-2log3
=-2*.477
=-0.954
..
2)log 30
=log 10*3
=log 10+log 3
=1+.477
=1.477
..
3)log 5
=log(30/6)
=log 30-log 6
=log 10+log3-(log 3+log 2)
=1+.477-.477-.301
=1-.301
=.699
..
4)log 0.006
=log 6*10^-3
=10^-3*log6
=log(.001)+(log3+log2)
=-3+(.301+.477)
=7.78*10^-4
=-2.222