SOLUTION: Write a point-slope equation for the line with the given slope that contains the given point.
m =-4/3 ; (7, −1)
This is what I did -4/3=y-(-1)/(x-7)
-4/3=y+1/x-7
-4(x-7
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-> SOLUTION: Write a point-slope equation for the line with the given slope that contains the given point.
m =-4/3 ; (7, −1)
This is what I did -4/3=y-(-1)/(x-7)
-4/3=y+1/x-7
-4(x-7
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Question 589820: Write a point-slope equation for the line with the given slope that contains the given point.
m =-4/3 ; (7, −1)
This is what I did -4/3=y-(-1)/(x-7)
-4/3=y+1/x-7
-4(x-7)=2(y+1)
-4x+28=2y+2
-4x=2y+2+28
-4x=2y+30
-2y=4x+30
-2y/-2=(4x+30)/-2
y=4x/-2+30/-2
y=-2x+-15
What did I do wrong here? Answer by John10(297) (Show Source):
You can put this solution on YOUR website! Hint: Use the point-slope formula to write:
Y - yo = m(x - x0)
y - (-1) = (-4/3(x - 7)
We can stop right there because it just asks point-slope equation (not slope-intercept formula y = mx + b).
Hope it helps:)
John10