SOLUTION: A woman is twice as old as her daughter. Five years ago the sum of their ages was 44. What are their present ages? I came up with x being the daughters age and 2x as the mothers ag

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Question 589686: A woman is twice as old as her daughter. Five years ago the sum of their ages was 44. What are their present ages? I came up with x being the daughters age and 2x as the mothers age so i put it into the equation
x+5+2x+5=44
3x=54
x=18
mums age:36
daughters age:18
but i dont know if this their current age or their age five years ago im confused can u please help me!!
Answer by htmentor(1343) About Me  (Show Source):
You can put this solution on YOUR website!
Let d = the present age of the daughter
Then the mother's current age = 2d
5 years ago the daughter's age was d - 5 and the mother's age was 2d - 5
The sum of their ages 5 yrs ago was 44:
d - 5 + (2d - 5) = 44
3d - 10 = 44
3d = 54
d = 18
So the daughter is 18 and the mother is 36 years old
Note that you had the correct answer, but you set up and solved your equations incorrectly!