SOLUTION: find an equation of the line through (0,4) and perpindicular to 3x-2y=7

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Question 58958: find an equation of the line through (0,4) and perpindicular to 3x-2y=7
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
3X-2Y=7
-2Y=-3X+7
Y=3/2X-7/2 THUS THIS LINE HAS A SLOPE OF 3/2
A PERPENDICULAR LINE WOULD HAVE A SLOPE OF -2/3 (A NEGATIVE RECIPRICAL) THUS
Y=mX+b FOR A LINE THROUGH (0,4) HAS A SLOPE OF -2/3 & A Y INTERCEPT OR 4 OR
Y=-2/3X+4