SOLUTION: How do I solve by elimination for 2r - 3s = -5 and 3r + 2s = 38?

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Question 589273: How do I solve by elimination for 2r - 3s = -5 and 3r + 2s = 38?
Answer by solver91311(24713) About Me  (Show Source):
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Find a pair of constants such that if you multiply the first equation by the first constant and the second equation by the second constant the result will be that the coefficients on one of the variables will be additive inverses, that is to say if one of the coefficients is , then the coefficient on the same variable in the other equation is .

Next add the two equations, term by term. The variable with the additive inverse coefficients will be eliminated because the coefficient on that variable in the sum equation will be zero.

Solve for the remaining variable. Substitute that value back into either of the original equations and then solve for the remaining variable.

John

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