SOLUTION: how do i put -3x^2+6x+9 into a(x-h)^+k form?!?!
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Question 588865
:
how do i put -3x^2+6x+9 into a(x-h)^+k form?!?!
Found 2 solutions by
jim_thompson5910, josmiceli
:
Answer by
jim_thompson5910(35256)
(
Show Source
):
You can
put this solution on YOUR website!
Start with the given expression.
Factor out the
coefficient
. This step is very important: the
coefficient
must
be equal to 1.
Take half of the
coefficient
to get
. In other words,
.
Now square
to get
. In other words,
Now add
and
subtract
inside the parenthesis. Make sure to place this after the "x" term. Notice how
. So the expression is not changed.
Group the first three terms.
Factor
to get
.
Combine like terms.
Distribute.
Multiply.
So after completing the square,
transforms to
. So
.
So
is equivalent to
.
So the equation
is now in vertex form
where
,
, and
Answer by
josmiceli(19441)
(
Show Source
):
You can
put this solution on YOUR website!
(1)
(2)
(3)
This is 3 equations and 3 unknowns, so
it should be solvable
Plug (1) into (2)
(2)
(2)
(2)
and
(3)
(3)
(3)
so,
check answer:
OK