SOLUTION: Hi, I am studying for my college placement test and there is a few math problems that i am having difficulty solving, 1st. square root of 75/2 + cube root of 2/4 = 2nd. 1

Algebra ->  Square-cubic-other-roots -> SOLUTION: Hi, I am studying for my college placement test and there is a few math problems that i am having difficulty solving, 1st. square root of 75/2 + cube root of 2/4 = 2nd. 1      Log On


   



Question 588700: Hi, I am studying for my college placement test and there is a few math problems that i am having difficulty solving,
1st. square root of 75/2 + cube root of 2/4 =
2nd. 1/2(n^2) - n = 190 my answer was n2-n-380=0 but i think is wrong the answer must equal 0
3rd. 10x^2+5x/5x my answer was 10x^2 but i think is wrong
4th. how to factor 3x^2-15x, the correct answer is 3x(x-5) but i dont know why or how they get those numbers
5th. (4x-7)^2= ? my answer was 16x^2+49 but i think is wrong

Found 2 solutions by KMST, mathhelp@:
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Once you are accepted, it may not be a bad idea to be placed in a lower level math class, if that class helps you understand math. Of course, that depends on the teacher. Some people believe math is a difficult subject, mastered by memorizing formulas and procedures. I believe math is about understanding the meaning (and memorizing) a few definitions, and using your own reasoning to get the rest.
1) sqrt%2875%2F2%29+%2B+root%283%2C2%2F4%29 = ?
For roots, the root of a product equals the product of the roots, and the root of a quotient is the quotient of the roots.
sqrt%2875%2F2%29=sqrt%2875%29%2Fsqrt%282%29 and root%283%2C2%2F4%29=root%283%2C2%29%2Froot%283%2C4%29, but those expressions are not the simplified forms expected.
To make things simple (and pretty), we do a lot of clever factoring, like
sqrt%2875%29=sqrt%2825%2A3%29=sqrt%2825%29%2Asqrt%283%29=5sqrt%283%29
and we do not like roots of any kind of root in denominators.
We could write a first step with roots in denominators and "fix" it later,but we can also fix it before, as in
sqrt%2875%2F2%29=sqrt%2875%2A2%2F4%29=sqrt%2875%2A2%29%2Fsqrt%284%29=sqrt%2875%2A2%29%2F2
Then,

So sqrt%2875%2F2%29+%2B+root%283%2C2%2F4%29+=+5sqrt%286%29%2F2%2Broot%283%2C4%29%2F2
EXPLANATIONS ADDED:
2) (1/2)n^2 - n = 190 can be transformed into an equivalent equation by multiplying both sides times 2, and then subrracting 380 from both sides:
%281%2F2%29n%5E2+-+n+=+190 --> 2%28%281%2F2%29n%5E2+-+n%29+=+2%2A190 --> 2%28%281%2F2%29n%5E2%29+-+2%2An+=+2%2A190 --> n%5E2+-+2n=380 --> n%5E2-2n-380=0
If you needed to solve it, you could use the quadratic formula, or complete the square, like this:
n%5E2+-+2n=380 --> n%5E2+-+2n%2B1=380%2B1 (adding 1 to both sides)
Then writing the left side as the equivalent square, and adding as indicated on the right side:
%28n-1%29%5E2=381 --> x=1+%2B-+sqrt%28381%29
3) (10x^2+5x)/5x=%2810x%5E2%2B5x%29%2F5x=2x%2B1 As you divide or multiply a sum, you do that to every one of the terms added. If something priced 4 dollars and 50 cents is sold at half price , it will cost 2 dollars and 25 cents. You divide by two both parts of the price.
In math class we call that very logical fact "the distribbutive property." It is the basis of the procedures for multiplication that we learn in elementary school. We multiply times a factor a large number by splitting that large number into a sum of smaller numbers, multiplying each samller number times the factor separately, and then adding. When you multiply 21 (20+1) times 4, you multiply the 1 to get 4 and the 2 tens (20) to get 8 tens (80), and then add up.
4) how to factor 3x%5E2-15x, the correct answer is 3x(x-5)
That is the distributive porperty again:
3x%28x-5%29=3x%2Ax-3x%2A5=3x%5E2-15
AND MORE EXPLANATIONS:
5) %284x-7%29%5E2= ?
The answer is not 16x%5E2%2B49.
That is just part of the answer, but you are missing something.
If you were to apply the distributive property, you would need to do it twice, like this:

However, algebra students learn what the end result is for a square of a sum, so they do not have to mess with the intermediate steps.
Suppose you have the sum of two expressions, like 4x and -7, but we will call those two expressions A and B, for short. The square of A+B is
%28A%2BB%29%5E2=A%5E2%2B2AB%2BB%5E2
You would remember that easier if I draw it
The surface area of the big square is %28A%2BB%29%5E2=%28A%2BB%29%28A%2BB%29
It is made of 2 squares with areas A%5E2=A%2AA and B%5E2=B%2AB, plus two rectangles, each with area A%2AB=AB
So the square of a sum (of two expressions) is the sum of the two squares plus the two rectangles.
So to calculate the square of 4x plus -7, we add the square of each, plus twice their product

Answer by mathhelp@(10) About Me  (Show Source):
You can put this solution on YOUR website!
(4x-7)^2
= 16x^2-56x+49
not 16x^2+49