SOLUTION: Sam had 5 pizzas for a party. Each pizza has 8 slices. Susie ate 1/3 of one pizza, James ate 4/5 of one pizza, Mark ate 1/2 of one pizza, Lisa ate 1/4 of one pizza, and Larry ate 7

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: Sam had 5 pizzas for a party. Each pizza has 8 slices. Susie ate 1/3 of one pizza, James ate 4/5 of one pizza, Mark ate 1/2 of one pizza, Lisa ate 1/4 of one pizza, and Larry ate 7      Log On


   

Question 588648: Sam had 5 pizzas for a party. Each pizza has 8 slices. Susie ate 1/3 of one pizza, James ate 4/5 of one pizza, Mark ate 1/2 of one pizza, Lisa ate 1/4 of one pizza, and Larry ate 7/8 of one pizza. If Sam wanted a whole pizza for himself did he have enough left to eat that much? How much pizza is left? Explain in detail how you know.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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Sam had 5 pizzas for a party. Each pizza has 8 slices. Susie ate 1/3 of one pizza,
James ate 4/5 of one pizza, Mark ate 1/2 of one pizza, Lisa ate 1/4 of one pizza, and Larry ate 7/8 of one pizza.
If Sam wanted a whole pizza for himself did he have enough left to eat that much?
How much pizza is left? Explain in detail how you know.
:
Let's try to do this using the total pieces of pizza; 5 * 8 = 40
Each pizza is 1/5 of the total
:
S: 1%2F3 * 1%2F5 = 1%2F15 = .067
J: 4%2F5 * 1%2F5 = 4%2F25 = .160
M: 1%2F2 * 1%2F5 = 1%2F10 = .100
L: 1%2F4 * 1%2F5 = 1%2F20 = .050
L: 7%2F8 * 1%2F5 = 7%2F40 = .175
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% of pizza eaten:.552
then 1.000 - .552 = .448 remains
.448 * 40 ~ 18 pieces left, well over 1 pizza which is 8 slices