SOLUTION: write equation in standard form for each hyperbola vertices (11,0) &' (-11,0) and conjugate axis length 8

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Question 588602: write equation in standard form for each hyperbola
vertices (11,0) &' (-11,0) and conjugate axis length 8
Answer by lwsshak3(11628) About Me  (Show Source):
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write equation in standard form for each hyperbola
vertices (11,0) &' (-11,0) and conjugate axis length 8
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Standard form of equation for a hyperbola with horizontal transverse axis:
(x-h)^2/a^2-(y-k)^2/b^2=1, (h,k) being the (x,y) coordinates of the center.
For given hyperbola:
center: (0,0)
length of horizontal transverse axis=22=2a (-11 to 11)
a=11
a^2=121
Given length of conjugate axis =8=2b
b=4
b^2=16
Equation of hyperbola:
x^2/121-y^2/16=1