SOLUTION: log(7)36-log(7)2x=log(7)4
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Question 588567
:
log(7)36-log(7)2x=log(7)4
Answer by
lwsshak3(11628)
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log(7)36-log(7)2x=log(7)4
log7(36)-log7(2x)-log7(4)=0
log7(36)-(log7(2x)+log7(4))=0
log7[36/2x*4]=0
convert to exponential form
7^0=36/8x=1
8x=36
x+36/8=9/2