SOLUTION: How do you graph the ellipse ((x-3))^2+((y-2/4))^2=1?
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Question 588441
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How do you graph the ellipse ((x-3))^2+((y-2/4))^2=1?
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lwsshak3(11628)
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How do you graph the ellipse
((x-3))^2+((y-2/4))^2=1
(x-3)^2+(y-1/2)^2=1
This is an equation of a circle with center at (3,1/2) and radius=1