SOLUTION: I'm confused about this problem.. I would really apprecate the help!! A bag contains 6 cherry, 3 orange, and 2 lemon candies. You reach in and take 3 pieces of candy at random

Click here to see ALL problems on Probability-and-statistics

Question 588415: I'm confused about this problem.. I would really apprecate the help!!

A bag contains 6 cherry, 3 orange, and 2 lemon candies. You reach in and take 3 pieces of candy at random. The probability that you have 1 cherry candy and 2 lemon candies is?
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website!
There are $\LARGE _{11}C_3 = \frac{11!}{3!(11-3)!} = 165$ different ways to select 3 candies

Note: this is assuming order doesn't matter

Of these 165 ways, there are only 6 ways to select 1 cherry candy and 2 lemon candies. Why 6? Since there are only 2 lemon candies and there are 3 slots, this means that there's only one slot left for the cherries. There are 6 cherries to fill that last slot.

So the probability is