SOLUTION: for each equation use the correct standard form to identify a,b,c x^2/16-y^2/4=1 x^2/9-y^2/36=1 y^2/25-x^2/4=1 x^2-4y^2=4 2y^2-10x^2=40 16y^2-4x^2=64 i do not understand how

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: for each equation use the correct standard form to identify a,b,c x^2/16-y^2/4=1 x^2/9-y^2/36=1 y^2/25-x^2/4=1 x^2-4y^2=4 2y^2-10x^2=40 16y^2-4x^2=64 i do not understand how       Log On


   

Question 587990: for each equation use the correct standard form to identify a,b,c
x^2/16-y^2/4=1
x^2/9-y^2/36=1
y^2/25-x^2/4=1
x^2-4y^2=4
2y^2-10x^2=40
16y^2-4x^2=64 i do not understand how to solve these problems or write them in standard form
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
for each equation use the correct standard form to identify a,b,c
x^2/16-y^2/4=1
x^2/9-y^2/36=1
y^2/25-x^2/4=1
x^2-4y^2=4
2y^2-10x^2=40
16y^2-4x^2=64
i do not understand how to solve these problems or write them in standard form
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All 6 are hyperbolas.
Standard form is
x%5E2%2Fa%5E2+-+y%5E2%2Fb%5E2+=+c%5E2
x^2/16-y^2/4=1
This is standard form
a = 4, b = 2, c = 1
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x^2/9-y^2/36=1
This is standard form
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y^2/25-x^2/4=1
This is standard form
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x^2-4y^2=4
Divide by 4
x%5E2%2F2%5E2+-+y%5E2%2F1+=+1
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2y^2-10x^2=40
Divide by 40
-x%5E2%2F4+%2B+y%5E2%2F20+=+1
a = 2, b = sqrt(20), c = 1
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16y^2-4x^2=64