SOLUTION: what is the radius of this equation x^2+y^2+16x+10y+80=0

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Question 587741: what is the radius of this equation x^2+y^2+16x+10y+80=0
Answer by lwsshak3(11628) About Me  (Show Source):
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what is the radius of this equation
x^2+y^2+16x+10y+80=0
complete the squares
(x^2+16x+64)+(y^2+10y+25)=-80+64+25
(x+8)^2+(y+5)^2=5
This is a circle with center at (-8,-5) and radius=√5
Standard form of equation for a circle: (x-h)^2+(y-k)^2=r^2, (h,k) being the coordinates of the center and r=radius.