SOLUTION: write an equation in slope intercept form for a line that passes through the given point and that is perpendicular to the given line. x= -7; (0,2)

Algebra ->  Linear-equations -> SOLUTION: write an equation in slope intercept form for a line that passes through the given point and that is perpendicular to the given line. x= -7; (0,2)      Log On


   



Question 587363: write an equation in slope intercept form for a line that passes through the given point and that is perpendicular to the given line. x= -7; (0,2)
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+x+=+-7+ is a vertical line through (-7,0)
Think of the equation as saying: " I am a line
that always sees -7 on the x-axis, and
I don't care what y is."
Any line perpendicular to this line will be a horizontal
line which means it has slope = 0.
If the general form of an equation is +y+=+m%2Ax+%2B+b+,
where m = slope, then I have
+y+=+0%2Ax+%2B+b+
+y+=+b+
The line goes through (0,2), which is on the y-axis
It intersects the given vertical line +x+=+-7+ at
(-7,2). Both these points tell me that the equation is
+y+=+2+