SOLUTION: Linda can stuff 1000 envelopes in 6 hours. If Laura helps her, they can both stuff 1000 envelopes in 5 ½ hours. How long would it take Laura to stuff 1000 envelopes by herself?

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Linda can stuff 1000 envelopes in 6 hours. If Laura helps her, they can both stuff 1000 envelopes in 5 ½ hours. How long would it take Laura to stuff 1000 envelopes by herself?      Log On


   

Question 58736This question is from textbook Elementry and Intermediate Algebra
: Linda can stuff 1000 envelopes in 6 hours. If Laura helps her, they can both stuff 1000 envelopes in 5 ½ hours. How long would it take Laura to stuff 1000 envelopes by herself? This question is from textbook Elementry and Intermediate Algebra

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Linda can stuff 1000 envelopes in 6 hours. If Laura helps her, they can both stuff 1000 envelopes in 5 ½ hours. How long would it take Laura to stuff 1000 envelopes by herself?
:
We don't care how many envelope, just let the completed job = 1
Let t = time required (in hrs) when Laura works by herself
:
5.5%2F6+5.5%2Ft = 1
:
multiply the equation by 6t, gets rid of the denominators, resulting in:
5.5t + 6(.5.5) = 6t
:
5.5t + 33 = 6t
:
5.5t - 6t = -33
:
-.5t = -33
:
t = -33/-.5
:
t = +66 hrs for Laura to do the job, obviously not much help
:
:
Check: 5.5/6 + 5.5/66 =
.9167 + .0833 = 1