SOLUTION: I'm trying to find how to solve for the following equation. Find the slope/intercept form of a linear equation that is perpendicular to Y=5x and passes through the point (-5,-

Algebra ->  Linear-equations -> SOLUTION: I'm trying to find how to solve for the following equation. Find the slope/intercept form of a linear equation that is perpendicular to Y=5x and passes through the point (-5,-      Log On


   

Question 58730This question is from textbook Algebra I
: I'm trying to find how to solve for the following equation.
Find the slope/intercept form of a linear equation that is perpendicular to Y=5x and passes through the point (-5,-5). Graph both lines to see that they are perpendicular.
Thank for the help
J.B. Gaskins This question is from textbook Algebra I

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Hi J.B. Gaskins
Find the slope/intercept form of a linear equation that is perpendicular to Y=5x and passes through the point (-5,-5). Graph both lines to see that they are perpendicular.
:
Perpendicular lines have slopes that are negative reciprocals of each other, they're opposite signs and upside down.
The line that they gave you is in slope intercept form:highlight%28y=mx%2Bb%29, m=slop, (0,b)=y-intercept.
y=highlight%285%29x the slope of this line is m=5
The slope of all lines perpendicular to this line is: m=-1/5
Use the point-slope formula highlight%28y-y1=m%28x-x1%29%29to find the perpendicular line going through (x1,y1)=(-5,-5).
y-%28-5%29=%28-1%2F5%29%28x-%28-5%29%29
y%2B5=%28-1%2F5%29%28x%2B5%29
y%2B5=%28-1%2F5%29x-%281%2F5%29%285%29
y%2B5=%28-1%2F5%29x-1
y%2B5-5=%28-1%2F5%29x-1-5
highlight%28y=%28-1%2F5%29x-6%29
graph%28300%2C200%2C-15%2C15%2C-10%2C10%2C5x%2C%28-1%2F5%29x-6%29
The red line is y=5x, the green one is y=(-1/5)x-6. They meet at a 90 degree angle and thus are perpendicular.
Happy Calculating, J.B. Gaskins!!!