SOLUTION: (w3 + 64) ÷ (4 + w) a. w² - 4w - 16 b. w² + 4w - 16 c. w² - 4w + 16

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: (w3 + 64) ÷ (4 + w) a. w² - 4w - 16 b. w² + 4w - 16 c. w² - 4w + 16       Log On


   



Question 587256: (w3 + 64) ÷ (4 + w)
a. w² - 4w - 16
b. w² + 4w - 16
c. w² - 4w + 16

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
(w3 + 64) ÷ (4 + w)
a. w² - 4w - 16
b. w² + 4w - 16
c. w² - 4w + 16
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You can try each answer, see which is correct, if any.
Or, divide and see what that answer is.
%28w%5E3+%2B+64%29%2F%28w%2B4%29
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Look at the sum of 2 cubes:
a%5E3+%2B+b%5E3+=+%28a%2Bb%29%2A%28a%5E2+-+ab+%2B+b%5E2%29