SOLUTION: Two cabins are observed by a ranger in a 60 feet tower above a park. The angles of depression are 11.6(degrees) AND 9.4(degrees). How far apart are the cabins?

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Question 587150: Two cabins are observed by a ranger in a 60 feet tower above a park. The angles of depression are 11.6(degrees) AND 9.4(degrees). How far apart are the cabins?
Answer by lwsshak3(11628) (Show Source):
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Two cabins are observed by a ranger in a 60 feet tower above a park. The angles of depression are 11.6(degrees) AND 9.4(degrees). How far apart are the cabins?
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let cabin A be furthest from the tower
let cabin B be closest to the tower
cabin A makes an angle of elevation of 9.4� with the tower (same as given angle of depression)
cabin B makes an angle of elevation of 11.6� with the tower (same as given angle of depression)
let x=distance from base of 60 ft tower to cabin A
let y=distance from base of 60 ft tower to cabin B
..
tan 9.4�=60/x
x=60/tan 9.4�≈362.43 ft
..
tan 11.6�=60/y
y=60/tan 11.6�≈292.30 ft
..
x-y=distance cabins are apart=362.43-292.30=70.13 ft