SOLUTION: The problem is 5w2-5w=0. I know w MUST equal zero (like x-4 x=4 because 4-4=0) So i did the GCF, and i got 1. When i tried to plug it back in i got: 5w2-5w=0 1w(5w-5)=0 But

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: The problem is 5w2-5w=0. I know w MUST equal zero (like x-4 x=4 because 4-4=0) So i did the GCF, and i got 1. When i tried to plug it back in i got: 5w2-5w=0 1w(5w-5)=0 But       Log On


   

Question 586853: The problem is 5w2-5w=0.
I know w MUST equal zero (like x-4 x=4 because 4-4=0)
So i did the GCF, and i got 1.
When i tried to plug it back in i got:
5w2-5w=0
1w(5w-5)=0
But i dont think that's right.
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
yes, w=0; but there is another solution ___ this is usually true for 2nd order (squared) equations

because of the zero product rule; when 1w(5w-5) = 0 ___ 1w = 0 AND 5w - 5 = 0

so w = 0 AND w = 1